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STPS1045B

ST Microelectronics
Part Number STPS1045B
Manufacturer ST Microelectronics
Description POWER SCHOTTKY RECTIFIER
Published Feb 25, 2007
Detailed Description www.DataSheet4U.com ® STPS1045B/H POWER SCHOTTKY RECTIFIER MAIN PRODUCT CHARACTERISTICS IF(AV) VRRM VF (max) FEATURES...
Datasheet PDF File STPS1045B PDF File

STPS1045B
STPS1045B

Overview
www.
DataSheet4U.
com ® STPS1045B/H POWER SCHOTTKY RECTIFIER MAIN PRODUCT CHARACTERISTICS IF(AV) VRRM VF (max) FEATURES AND BENEFITS n n n n 10 A 45 V 0.
57 V K K NEGLIGIBLE SWITCHING LOSSES LOW FORWARD DROP VOLTAGE LOW CAPACITANCE HIGH REVERSE AVALANCHE SURGE CAPABILITY K A A A K A DESCRIPTION High voltage Schottky rectifier suited for Switch Mode Power Supplies and other Power Converters.
Packaged in DPAK and IPAK, these devices are intended for use in high frequency circuitries where low switching losses are required.
DPAK STPS1045B IPAK STPS1045H ABSOLUTE MAXIMUM RATINGS Symbol VRRM IF(RMS) / pin IF(AV) IFSM IRRM Tstg Tj dV/dt Parameter Repetitive peak reverse voltage RMS forward current / pin Average forward current Surge non repetitive forward current Repetitive peak reverse current Storage temperature range Maximum junction temperature Critical rate of rise of reverse voltage Tc = 150°C d = 0.
5 tp = 10 ms Sinusoidal tp = 2 µs F = 1KHz Value 45 7 10 75 1 - 65 to + 175 175 10000 Unit V A A A A °C °C V/µs May 2000 - Ed: 2B 1/5 STPS1045B/H THERMAL RESISTANCES Symbol Rth (j-c) Junction to case Parameter Value 3 Unit °C/W STATIC ELECTRICAL CHARACTERISTICS Symbol IR * VF ** Parameter Reverse leakage current Forward voltage drop Tests Conditions Tj = 25°C Tj = 125°C Tj = 25°C Tj = 125°C Tj = 25°C Tj = 125°C Pulse test : * tp = 380 µs, δ < 2 % **tp = 5 ms, δ < 2% Min.
Typ.
7 Max.
100 15 0.
63 0.
57 0.
84 0.
72 Unit µA mA V VR = 45 V IF = 10 A IF = 10 A IF = 20 A IF = 20 A 0.
65 0.
5 To evaluate the maximum conduction losses use the following equation : P = 0.
42 x IF(AV) + 0.
015 IF2(RMS) Fig.
1: Average forward power dissipation versus average forward current.
PF(av)(W) 8 7 6 5 4 3 2 1 0 0 1 2 3 4 IF(av) (A) 5 6 7 8 9 δ=tp/T T Fig.
2: Average forward current versus ambient temperature (δ=0.
5).
IF(av)(A) δ = 0.
05 δ = 0.
1 δ = 0.
2 δ = 0.
5 12 Rth(j-a)=Rth(j-c) 10 δ=1 8 6 4 T Rth(j-a)=15°C/W Rth(j-a)=70°C/W 2 tp 10 11 12 0 δ=tp/T tp Tamb(°C) 50 7...


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